If the mobile phase had traveled 8.1 cm, how far would a spot containing the same substance have traveled?

hello your question is incomplete below is the complete question

Suppose that there are two components A and B, in a mixture. The chemical affinity of A for the stationary phase is less than that of B and the chemical affinity of A for the mobile phase is greater than that of B. If the mixture is subject to paper chromatography

answer : 5.751 cm

Explanation:

lets make an assumption that the RF value of A = 0.71

therefore when a solvent travels 8.1 cm with such conditions

The distance travelled by a spot containing the same substance

= Rf . 8.1 cm

= 0.71 * 8.1 = 5.751 cm

indicate valleys, hills, steepness and gentleness of slopes.

explanation:

contour lines on a map indicate elevation, or depth. numeric notations on contour lines refer to the level of elevation, or height about sea level.