Chemistry, 18.01.2021 19:40 pattydixon6
Elimination of HBr from 2-bromobutane affords a mixture of but-1-ene and but-2-ene. With sodium ethoxide as base, but-2-ene constitutes 81% of the alkene products, but with potassium tert-butoxide, but-2-ene constitutes only 67% of the alkene products. Offer an explanation for this difference.
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Elimination of HBr from 2-bromobutane affords a mixture of but-1-ene and but-2-ene. With sodium etho...
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