The density of water at 60.0 °C is 0.9832 g/mL. If the specific gravity of acetic acid is 1.023 at 60.0 °C, what is the density of acetic acid at 60.0 °C?

1.0058 g/mL

Explanation:

Note: Specific gravity of a substance is same as the relative density.

R.D = Density of the substance/ Density of water.

R.D = D/D' Equation 1

Make D the subject of the equation

D = R.D×D' Equation 2

Where R.D = Specific gravity of acetic acid, D = density of acetic acid, D' = density of water.

At 60°C,

R.D = 1.023, D' = 0.9832 g/mL

Substitute into equation 2

D = (1.023×0.9832)

D = 1.0058 g/mL

Hence the density of acetic at 60°C is  1.0058 g/mL

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.