The net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is

 + 2NaOH → Na2SO4 + 2H2O

The ionic equation omits ions which act as spectators so we can split the reactants and the products into ions to see which are the spectators.

H2SO4 → 2H+ + (SO4)2-

NaOH → Na+ + (OH)-

Na2SO4 → 2Na+ + (SO4)2-

(sodium salts are generally soluble and dissociate into their ions when in solution)

H2O exists in the molecular form

So we get 2H+ + (SO4)2- + 2Na+ + 2(OH)- →2Na+ + (SO4)2- + 2H2O

We see that Na+ and (SO4)2- appears on both sides of the equation, hence they are spectators and can be removed in the ionic equation.

So we get 2H+ + 2(OH)- → 2H2O effectively as the ionic equation.

It is good practice to give the equation in the simplest number ratio and hence the net ionic equation is H+ + (OH)- → H2O

Explanation:

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;