Chemistry, 19.01.2021 04:40 tiffxnnyyy

For the following reaction, 2.70 grams of methane (CH4) are allowed to react with 30.0 grams of carbon tetrachloride . methane (CH4)(g) carbon tetrachloride(g) dichloromethane (CH2Cl2)(g) What is the maximum mass of dichloromethane (CH2Cl2) that can be formed

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Answer from: lulbbyz

28.69 g of CH₂Cl₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CH₄ + CCl₄ —> 2CH₂Cl₂

Next, we shall determine the masses of CH₄ and CCl₄ that reacted and the mass of CH₂Cl₂ produced from the balanced equation. This is illustrated below:

Molar mass of CH₄ = 12 + (4×1)

= 12 + 4 = 16 g/mol

Mass of CH₄ from the balanced equation = 1 × 16 = 16 g

Molar mass of CCl₄ = 12 + (4×35.5)

= 12 + 142 = 154 g/mol

Mass of CCl₄ from the balanced equation = 1 × 154 = 154 g

Molar mass of CH₂Cl₂ = 12 + (2×1) + (2×35.5)

= 12 + 2 + 71 = 85 g/mol

Mass of CH₂Cl₂ from the balanced equation = 2 × 85 = 170 g

SUMMARY:

From the balanced equation above,

16 g of CH₄ reacted with 154 g of CCl₄ to produce 170 g of CH₂Cl₂.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

16 g of CH₄ reacted with 154 g of CCl₄.

Therefore, 2.7 g of CH₄ will react with = (2.7 × 154)/16 = 25.99 g of CCl₄

From the calculations made above, we can see that only 25.99 g of CCl₄ out of 30 g given is required to react completely with 2.7 g of CH₄.

Therefore, CH₄ is the limiting reactant and CCl₄ is the excess reactant.

Finally, we shall determine the maximum mass of CH₂Cl₂ produced from the reaction.

In this case, the limiting reactant will be used because it will produce the maximum mass of CH₂Cl₂ since all of it is consumed in the reaction.

The limiting reactant is CH₄ and the maximum mass of CH₂Cl₂ produce can be obtained as follow:

From the balanced equation above,

16 g of CH₄ reacted to produce 170 g of CH₂Cl₂.

Therefore, 2.7 g of CH₄ will react to produce = (2.7 × 170)/16 = 28.69 g of CH₂Cl₂.

Thus, 28.69 g of CH₂Cl₂ were obtained from the reaction.

Answer from: Quest

c8h10 is your answerr

Answer from: Quest

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

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For the following reaction, 2.70 grams of methane (CH4) are allowed to react with 30.0 grams of carb...

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