SO2 +
Li2Se → __SSe2 +
Li2O

We want to take inventory of the right and left side Right: S=1 O = 2 Li = 2 Se= 1 Left: S= 1 Se=2 Li= 2 O=1Lets balance out each side because we see we are off by 1 oxygen on the left Add a coefficient of 2 on the Li2OAdd a coefficient of 2 on the right Li2Se Now we have So2+ 2Li2Se ---> SSe2+ 2Li2O

How do we find the answer?

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.