Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide what lithium diorganocopper (Gilman) reagent is needed to convert 1-bromopropane into 1-hexene.

Explanation:

Gilman reagent is also known as the Lithium organocuprates. They are used as nucleophiles in the organic synthesis.

Gilman reagent is used for C - C bond formation.

                                                            H    H    H

                                                             |      |      |

              -----→     H  - C -- C -- C -- C =

           (1 bromo propane)                   |      |     |       |

                                                           H     H   H     H

                                                             (1 pentene)

Normally in C--C formation by Gilman reagent, the following reactions takes place :

R -- Br   +    R--R' + R' Cu + Li Br

In 1 pentene, i.e.

(from 1 bromo    (from Gilman reagent)

      propane)

So Gilman reagent is

Organo lithium compound is

mention the spill to the teacher clean the area and throw the broken pieces away

explanation:

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).