Calculate the concentration of 10g of magnesium chloride in 1dm3 of solution.

Concentration is

Given:-

Mass of MgCl₂ = 10 g

Volume of solution =

Concentration of MgCl₂ =?

 Mole of MgCl₂ =?

The number of moles is calculated by the equation as follows:-

Determine the concentration of as follows:-

Mole of MgCl₂ = 0.105 mole

Volume of solution = 1 dm³

Concentration of MgCl₂ =?

Hence the concentration of 10g of magnesium chloride is .

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0.105 mol/dm³

Explanation:

From the question given above, the following data were obtained:

Mass of MgCl₂ = 10 g

Volume of solution = 1 dm³

Concentration of MgCl₂ =?

Next, we shall determine the number of mole present in 10 g of MgCl₂. This can be obtained as follow:

Mass of MgCl₂ = 10 g

Molar mass of MgCl₂ = 24 + (2 ×35.5)

= 24 + 71

= 95 g/mol

Mole of MgCl₂ =?

Mole = mass /Molar mass

Mole of MgCl₂ = 10 / 95

Mole of MgCl₂ = 0.105 mole

Finally, we shall determine the concentration of MgCl₂. This can be obtained as follow:

Mole of MgCl₂ = 0.105 mole

Volume of solution = 1 dm³

Concentration of MgCl₂ =?

Concentration = mole / Volume

Concentration of MgCl₂ = 0.105 / 1

Concentration of MgCl₂ = 0.105 mol/dm³

the answer is either b or c