What is the [H ] of a solution of 0.001 M aqueous sulfuric acid (H2SO4) is H2SO4 ionizes in water according to the balanced chemical equation below? H2SO4 --> 2 H+ + SO42-

 0.002 M

Explanation:

The balanced chemical equation for ionization of in water is:

According to stoichiometry :

1 mole of ionizes to give =2 mole of ions

0.001 mole of ionizes to give = mole of ions

Thus of a solution of 0.001 M aqueous sulfuric acid is 0.002 M

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

58750.08068 is the answer i think