How is the oxidation state of a transition metal determined from the chemical formula?

A. A superscript on the transition metal identifies its oxidation state

in the formula.

B. The subscript of the transition metal in the formula identifies its

oxidation state.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

D. The total charge of the negative ion identifies the oxidation state

of the transition metal.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

Explanation:

A. A superscript on the transition metal identifies its oxidation state

in the formula.

This is wrong! Superscript are usually not written in formula of compound and for those that have superscripts, it refers to the oxidation number of the compound as a whole.

B. The subscript of the transition metal in the formula identifies its

oxidation state.

This is wrong! Subscripts shows how many atoms of the element is present.

C. A Roman numeral placed after the transition metal identifies its

oxidation state.

This is correct! Examples include; manganese (II) oxide, Potassium manganate (VII) etc

D. The total charge of the negative ion identifies the oxidation state

of the transition metal.

This is wrong! Because there are cases of other metals or cations being present in the compound aside the transition metal

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.