Calculate the mass of 6.9 moles of nitrous acid (HNO2). Explain the process or show your work by including all values used to determine the answer. (5 points) IF YOU GET THIS CORRECT IM GIVING YOU BRAINLIEST

Explanation:

Known Background Information:

Therefore molar mass of HNO2

= (1g/mol + 14g/mol + 2 * 16g/mol) = 47g/mol.

Hence mass of HNO2

= Molar mass * Number of moles

= (47g/mol) * (6.9mol)

= 324.3g.

Explanation:

Known Background Information:

Molar mass of H: 1g/mol

Molar mass of N: 14g/mol

Molar mass of O: 16g/mol

Therefore molar mass of HNO2

= (1g/mol + 14g/mol + 2 * 16g/mol) = 47g/mol.

Hence mass of HNO2

= Molar mass * Number of moles

= (47g/mol) * (6.9mol)

= 324.3g.

Explanation:

if you mean hydrogen and oxygen then water is the product

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