What is the molarity of a solution with 1.43 moles of sodium chloride in 0.875 liters of solution?

1.63 M

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtract Property of Equality

Chemistry

Unit 0

Reading a Periodic TableWriting Compounds

Aqueous Solutions

Molarity = moles of solute / liters of solutionExplanation:

Step 1: Define

1.43 mol NaCl (sodium chloride)

0.875 L solution

Step 2: Find M

Substitute [M]:                      x M = 1.43 mol NaCl / 0.875 LDivide:                                   x = 1.63429 M

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.63429 M ≈ 1.63 M

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