How many moles of bromine gas are produced when fluorine reacts with 347.5 g of potassium
bromide?

1.46 mol

Explanation:

Given data:

Moles of bromine gas produced = ?

Mass of potassium bromide = 347.5 g

Solution:

Chemical equation:

2KBr  +  F₂   →  2KF + Br₂

Number of moles of KBr:

Number of moles = mass/ molar mass

Number of moles = 347.5 g/ 119.0 g/mol

Number of moles = 2.92 mol

Now we will compare the moles of KBr and bromine.

                  KBr       :     Br₂

                    2         :      1

                   2.92    :       1/2×2.92 = 1.46 mol

just did the assignment and the answer was #1 +2 n

the ratio of the conjugate base to the acid required to attain the desired ph.