A single gold atom has a mass of 197.0 amu. How many gold atoms are in a cube of gold that is 10.0 mm on each side (about the size of a sugar cube) if the density of gold is 19.3 g/cm3

5.90x10²² atoms of gold are present in the cube

Explanation:

First, we must find the volume of the cube in cm³. With density we can find the mass of the gold and the moles using its molar mass. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:

Volume in cm³:

(10.0mm)³ = 1000mm³

1mm³ = 0.001cm³

1000mm³ * (0.001cm³ / 1mm³) = 1cm³

Mass gold:

1cm³ * (19.3g/cm³) = 19.3g Gold

Moles Gold:

19.3g * (1mol / 197.0g) = 0.0980 moles Gold

Atoms gold:

0.0980 moles Gold * (6.022x10²³ atoms / mol) =

5.90x10²² atoms of gold are present in the cube

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.

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