A solution is made by mixing of chloroform and of heptane . Calculate the mole fraction of chloroform in this solution. Be sure your answer has the correct number of significant digits.

0.53

Explanation:

A solution is made by mixing 42 g of chloroform (CHCl₃) and 31 g of heptane (C₇H₁₆). Calculate the mole fraction of chloroform in this solution. Be sure your answer has the correct number of significant digits.

Step 1: Calculate the number of moles of chloroform

The molar mass of CHCl₃ is 119.38 g/mol.

42 g × 1 mol/119.38 g = 0.35 mol

Step 2: Calculate the number of moles of heptane

The molar mass of C₇H₁₆ is 100.20 g/mol.

31 g × 1 mol/100.20 g = 0.31 mol

Step 3: Calculate the total number of moles

We will use the following expression.

n = nCHCl₃ + nC₇H₁₆ = 0.35 mol + 0.31 mol = 0.66 mol

Step 4: Calculate the mole fraction of chloroform

We will use the following expression.

χ(CHCl₃) = nCHCl₃ / n

χ(CHCl₃) = 0.35 mol / 0.66 mol = 0.53

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.