1. Write the balanced chemical equation for the reaction you are performing.
2. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of Mg, crucible, and lid (row 2 in the chart) to find the mass of magnesium for each trial.
• Trial 1: 0.252
• Trial 2: 0.406
3. Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 3 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yield of magnesium oxide for each trial.
• Trial 1: 0.413
• Trial 2: 0.459
4. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
• Trial 1:
• Trial 2:
5. Determine the percent yield of MgO for your experiment for each trial.
• Trial 1:
• Trial 2:
6. Determine the average percent yield of MgO for the two trials.
Answers: 1
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1. Write the balanced chemical equation for the reaction you are performing.
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