How many liters of C4H10 are present in 0.25 moles of C4H10 at STP?

V = 5.6 L

Explanation:

Given data:

Number of moles of C₄H₁₀ = 0.25 mol

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Volume of C₄H₁₀ = ?

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L /mol.K

1 atm × V = 0.25 mol ×  0.0821 atm.L /mol.K × 273.15 K

V = 5.6 atm.L/ 1 atm

V = 5.6 L

the answer would be c