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The answer is 10.8 g of lH2.

Explanation:

As per the equation, let us calculate the mole ratio.

N2+3H2→2NH3

As per the equation one mole of nitrogen reacts with 1 mol of hydrogen.

In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.

We can set up the ratio:

28.01 g of lN2 needs 6.048 g of lH2

1 g of lN2 needs 6.048 / 28.01 g of lH2

50.0 g of lN2 needs 6.048×50.0 28.01 lg of lH2

=

10.8 g of lH2

Hope this helps!! ;)

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.