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Mass of NaCl : 5.85 g

Given

5.3 g Sodium carbonate (Na₂CO₃)

Required

Mass of NaCl

Solution

Reaction

Na₂CO₃ + 2HCl ⇒ 2NaCl + H₂O + CO₂

mol of Na₂CO₃ (MW=106 g/mol) :

= mass : MW

= 5.3 g : 106 g/mol

= 0.05

From the equation, mol ratio Na₂CO₃ : NaCl = 1 : 2, so mol NaCl :

= 2/1 x mol Na₂CO₃

= 2/1 x 0.05

= 0.1

Mass of NaCl (MW=58.5 g/mol) :

= mol x MW

= 0.1 x 58.5

= 5.85 g

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

b is the correct answer

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