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Chemistry, 24.01.2021 03:40 dmgcity

Compounds Lab Report Instructions: In this virtual lab you will build chemical compounds from known elements. Record your hypothesis and compound results in the lab report below. You will submit your completed report to your instructor.

Note: If you cannot complete this lab as directed, please contact your instructor for assistance.

Name and Title:

Include your name, instructor's name, date, and name of lab.

Objectives(s):

In your own words, what is the purpose of this lab?

Hypothesis:

In this section, please include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.

Procedure:

The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome. Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.

Data:

Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.

Compound NameChemical FormulaSodium (Na) AtomsCalcium (Ca) AtomsHydrogen (H) AtomsOxygen (O) AtomsCarbon (C) AtomsChlorine (Cl) Atoms
Ex: Sodium
hypochloriteNaClO100101

Conclusion:

Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

Using two to three sentences, summarize what you investigated and observed in this lab.
Why do you believe knowing how elements and compounds react together is essential in everyday matters?
Some elements are more "reactive" than other elements; why do you think this is?
Choose one of the compounds from the table and explain how you know the numbers of atoms in your formula.
Is it possible for two different compounds to be made from the exact same two elements? Why or why not? With a limited number of elements (less than 120 are known), does this mean we also have a small number of compounds or do we have a large number of compounds in this world?

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Maleic acid is a carbon-hydrogen-oxygen compound used in dyeing and finishing fabrics and as a preservative of oils and fats.* in a combustion analysis, a 1.054-g sample of maleic acid yields 1.599 g of co_2 and 0.327 g of h2o.* when 0.609 g of maleic acid is dissolved in 25.00 g of glacial acetic acid, the freezing point drops by 0.82 c. maleic acid does not ionize in glacial acetic acid, which has a freezing-point depression constant of k_{\rm f}=3.90~^\circ {\rm c}/m.* in a titration experiment, a 0.4250- g sample of maleic acid is dissolved in water and requires 34.03 ml of 0.2152 m koh for its complete neutralization.* the ph of 0.215 g of maleic acid in 50.00 ml of aqueous solution is found to be 1.80.part adetermine the empirical formula for maleic acid. enter the atoms in order ofc, h, and o.part bdetermine the molecular formula for maleic acid. enter the atoms in order of c,h, and o.express your answer as a chemical formula.part cbased on the titration data, how many ionizable h atoms are in each molecule of maleic acid, c4h4o4? express your answer as an integer.i got the part a and b which is cho and c4h4o4 respectively, can anyone me for part c? the below is what i have so far from other qa'sfinding the empirical formula for maleic acid, needs this info"a combustion analysis a 1.054-g sample of maleic acid yields 1.599g of and 0.327g of ".the rest of your data is used to find molar mass, molecular formula, equivalent mass, # of h+ ions / molecule & katypically this should be: a 1.054-g sample of maleic acid yields 1.599g of co2 and 0.327g of h2osofind mass using molar masses1.599g of co2 @ (12.01 g carbon) / (44.01 g co2) = 0.436 grams of carbon0.327g of h2o @ (2.016 g hydrogen) / (18.01 g/mol h2o) = 0.037 grams of hydrogen1.054-g sample - 0.436 grams of carbon - 0.037 grams of hydrogen = 0.581 grams of oxygennow use molar masses to find moles0.436 grams of carbon @ 12.01 g/mol = 0.0363 mol c0.037 grams of hydrogen @ 1.008 g/mol = 0.0367 mol h0.581 grams of oxygen @ 16.00 g/mol = 0.0363 mol oyour empirical formula ischo and molecular is c4h4o4
Answers: 3
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Compounds Lab Report Instructions: In this virtual lab you will build chemical compounds from known...
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