At 27.8 °C, a gas occupies 1500 mL. What volume will it have at 100.0 °C?

V₂  = 1866.32 mL

Explanation:

Given data:

Initial temperature = 27.8°C (27 + 273.15 K = 300.15 k)

Initial volume = 1500 mL

Final volume = ?

Final temperature = 100.0°C (100.0 + 273.15 K = 373.15 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

1500 mL / 300.15 k = V₂ / 373.15 K

V₂  = 1500 mL× 373.15 K/ 300.15 k

V₂  = 560175 mL. K /300.15 k

V₂  = 1866.32 mL

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.

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