An old 0.500 L lecture bottle of triethylamine (N(CH₂CH₃)₃) was found in a lab and needed for a synthesis reaction. A pressure regulator indicated a pressure of 18.5 psi, and the lab was at room temperature (25.0°C). What mass of vaporized triethylamine in grams was left in the lecture bottle?

Mass of vaporized triethylamine : 2.606 g

Given

0.5 L triethylamine

P = 18.5 psi

T = 25 °C

Required

mass of vaporized triethylamine

Solution

Conversion :

P 18.5 psi = 1,26 atm

T = 25 +273 = 298 K

Ideal gas law :

PV=nRT

n = PV/RT

Input the value :

n = (1.26 atm x 0.5 L) /(0.08205 x 298)

n = 0.0258

MW triethylamine = 101 g/mol

Mass  triethylamine :

= n x MW

= 0.0258 x 101 g/mol

= 2.606 g

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

alchemy hadn't scientific methods of study, appeal to mysticism and fantasy, the knowledge of chemistry and physics were modest at that time.

alchemy was - but as new rules were discovered it either changed into chemistry or it became "unscientific".