The analysis of 2.12 of a compound gave 0.33 of carbon, 1.82 of the same compound gave 1.53 of sulphur. Calculate the emperical formula

CS₂

Explanation:

To find the empirical formula we need to determine first the percentage of each atom in the molecule. Then, we need to find the moles and, as empirical formula is the simplest whole-number ratio of atoms we can solve the empirical formula:

%C:

0.33gC / 2.12g * 100 = 15.6%

%S:

1.53g S / 1.82g * 100 = 84.1%

In a basis of 100, the moles of each atom are:

C:

15.6g C * (1mol / 12.01g) = 1.30 moles

S:

84.1g S * (1mol / 32.065g) = 2.62 moles

The ratio of Sulphur-Carbon is:

2.62mol / 1.30mol = 2

That means empirical formula is:

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

it means there are 3 atoms of oxygen