A sample of saturated clay was placed in a container and weighed. The weight was 6N. The clay in its container was placed in an oven for 24 hours at 105° C. The weight reduced to a constant value of 5N. The weight of the container is 1N. If G-2.7, determine the: (a) water content;
(b) void ratio;
(c) bulk unit weight;
(d) dry unit weight;
(e) effective unit weight.

Answer is given below

Explanation:

given data

weight = 6N

temp = 105° C

weight reduced = 5N

solution

weight of container is 1N

SO W = (6-1) = 5

And Wd = 5 - 1 = 4

so

moisture content is

moisture content =       .......1

moisture content =

moisture content = 25%

and

as we know density of soil soild = 2700 kg/m³

density of water = 1000 kg/m³

and sp gravity of soil =    = 2.7

so

now we get here bulk unit weight

bulk unit wt =     ..........2

bulk unit wt =

bulk unit wt = 19.766 KN/m³

and

so dry unit wt  will be

dry unit wt =           ..............3

dry unit wt =

dry unit wt = 15.813 kN/m³

1.solid

2.carbon dioxide

3.helium

i think it is true since you can test the answer and can use observations to complete it.