What mass of ZnCI2 can be prepared from the reaction of 3.27 grams of zinc with 3.30 grams of HCI? Zn + 2HCI —-> ZnCI2 + H2

Zn. + 2 HCl > ZnCl2. + H2

Explanation:

Mass of Zn in mole = 3.27/ 65.38= 0.050010 mol

Mass of HCl in mole = 3.3/ 73= 0.044mol

Hence, limiting reagent is HCl

Molar mass of ZnCl2= 136.38g

Let mass of ZnCl2 be x

x = 3.3*136.38÷ 73 = 6.165...

So, the mass of ZnCl2 is 6.17 g