How many moles of carbon dioxide, CO2, are produced when 4.50 moles of propane, C3H8, react?

Moles of Carbon dioxide : 13.5

Given

4.5 moles propane

Required

moles of Carbon dioxide

Solution

Reaction(Combustion of Propane) :

C₃H₈(g)+5O₂(g)→3CO₂(g)+4H₂O(g)

In a chemical equation, the reaction coefficient shows the mole ratio of the reacting compounds (either in reactants or products)

From the equation, mol ratio of Propane(C₃H₈) : Carbon dioxide(CO₂) : 1 : 3, so mol CO₂ :

= 3/1 x mol Propane

= 3 x 4.5 moles

= 13.5 moles

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :