2.At 35°C, a small sample of methane gas (CH4) has a volume of 1.5 liters. The temperature of the methane gas is slowly cooled to 17°C. What is the new volume of the methane sample?

V₂ = 1.41 L

Explanation:

Given data:

Initial temperature = 35°C (35 +273.15 K = 308.15 K)

Initial volume = 1.5 L

Final temperature = 17°C (17+273.15 K = 290.15 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1.5 L × 290.15 K / 308.15 k

V₂ = 435.23 L.K / 308.15 k

V₂ = 1.41 L

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.