What is the mass of 2.53x10^34 atoms of Ni?

2.48 g

Explanation:

From the question given above, the following data were obtained:

Number of atoms = 2.53×10³⁴ atoms

Mass of Ni =?

From Avogadro's hypothesis,

we understood that 1 mole of any substance contains 6.02×10²³ atoms.

Therefore, 1 mole of Ni contains 6.02×10²³ atoms.

Recall:

1 mole Ni = 59 g

Therefore, 59 g of Ni contains 6.02×10²³ atoms.

Finally, we shall determine the mass of 2.53×10³⁴ atoms of Ni. This can be obtained as follow:

6.02×10²³ atoms = 59 g

Therefore,

2.53×10³⁴ = 2.53×10³⁴ × 59 / 6.02×10²³

2.53×10³⁴ atoms = 2.48 g

Thus, the mass of 2.53×10³⁴ atoms of Ni is 2.48 g.

the correct answer would be b) volume versus temperature, because they are also directly proportional.