What mass of manganese(ii) chloride must react with sulfuric acid to release 52.5 ml of hydrogen chloride gas at stp?
mncl2(s)+h2so4(aq)→mnso4(aq)+2hcl(g )

The balanced chemical reaction is written as:

MnCl2(s)+H2SO4(aq)→MnSO4(aq)+2HCl(g)

We are given the amount of hydrochloric acid to be produced in the reaction. This value will be the starting point for the calculations.We do as follows:

.0525 L HCl ( 1 mol / 22.4 L ) ( 1 mol MnCl2 / 2 mol HCl ) (125.84 g / 1 mol ) = 0.15 g MnCl2

A) the enthralling of formation for pure element in its standard state is always positivehope this : )