Balance the Chemical Equations

Rb + RbNO3---> Rb2O + N2

please help me

10Rb° + 2RbNO₃  =>  6Rb₂O + N₂

Explanation:

Given:   Rb° + RbNO₃ => Rb₂O + N₂

=> 1st balance rubidium in RbNO₃ against Rb₂O  by inserting a '2' coefficient before RbNO₃ and a '6' coefficient  before Rb₂O

=> Rb° + 2RbNO₃  =>  6Rb₂O + N₂   => Oxygen and Nitrogen are balanced. All that remains is balancing Rb by inserting a '10' coefficient.

=>  10Rb° + 2RbNO₃  =>  6Rb₂O + N₂

Note: In balancing chemical equations, saving an element that is not part of a compound until last frequently gives balance by inspecting the number of elements of the specific kind and boosting its coefficient to balance the equation.  

Balanced equation =>  10Rb° + 2RbNO₃  =>  6Rb₂O + N₂

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