What is the molarity of 350 mL solution that has had 32.0 g of NaCl dissolved in it?

Molarity = 1.57 M

Explanation:

Given data:

Volume of solution = 350 mL (350 mL × 1L /1000 ml = 0.35 L)

Mass of NaCl = 32.0 g

Molarity of solution = ?

Solution:

Number of moles of solute:

Number of moles = mass/molar mas

Number of moles = 32.0 g/ 58.44 g/mol

Number of moles = 0.55 mol

Molarity:

Molarity = number of moles / volume in L

Molarity = 0.55 mol / 0.35 mL

Molarity = 1.57 mol/L

Molarity = 1.57 M

what's the

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.