How many moles of carbon dioxide are produced when 23.0 g of C3H2O3 is burned during the complete combustion of C3H2O3?
O 33.0 mol
O 0.250 mol
O 0.750 mol
O 3.00 mol
O 0.0833 mol

Moles of Carbon dioxide : 0.75

Given

23 g C₃H₈O₃

Required

Moles of Carbon dioxide

Solution

Reaction

2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O

mol C₃H₈O₃ :

= mass : MW

= 23 g : 92,09382 g/mol

= 0.24975

From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :

= 3/1 x mol C₃H₈O₃

= 3/1 x 0.24975

= 0.74925≈0.750 mol

its mg hope this