CH4 + 202 → CO2 + 2H2O
How many grams of O2 needed to react with 2 moles of CH4?

100 g O₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   2 mol CH₄

[Solve]   x g O₂

Step 2: Identify Conversions

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

Step 3: Stoichiometry

Step 4: Check

Follow sig fig rules and round. We are given 1 sig fig.

128 g O₂ ≈ 100 g O₂

Mass of O₂= 128 g

Given

Reaction

CH₄ + 20₂ → CO₂ + 2H₂O

2 moles of CH₄

Required

Mass of O₂

Solution

In a chemical equation, the reaction coefficient shows the mole ratio of the compounds involved in the reaction, reactants or products

From the equation, mol ratio of CH₄ : O₂ = 1 : 2, so moles O₂ :

= 2/1 x moles CH₄

= 2/1 x 2

= 4 moles

Mass of O₂ :

= mol x MW

= 4 x 32 g/mol

= 128 g

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explanation: