How many liters is 1.9 mol of Cl2 at STP?

V = 42.6 L

Explanation:

Given data:

Number of moles of Cl₂ = 1.9 mol

Temperature and pressure = standard

Volume occupy = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm ×  V = 1.9 mol ×0.0821 atm.L /mol.K × 273.15 k

V = 42.6  atm.L / 1 atm

V = 42.6 L

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