How many grams is 4.15 liters of O2 at stp?

Mass = 5.92 g

Explanation:

Given data:

Volume of O₂ = 4.15 mol

Temperature and pressure = standard

Mass in gram = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

By putting values,

1 atm × 4.15L = n ×0.0821 atm.L /mol.K × 273.15 k

4.15 atm.L = n ×22.43 atm.L /mol

n = 4.15 atm.L / 22.43 atm.L /mol

n = 0.185 mol

Mass in gram:

Mas = number of moles × molar mass

Mass = 0.185 mol ×32g/mol

Mass = 5.92 g

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

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