How many grams of Ca ( OH )2 , ( Mwt = 74 g / mol ) exists in 2500 mL of 0.0250 M Ca ( OH )2 ?

4.6g

Explanation:

We are given the following parameters:

Molecular weight of the compound  = 74g/mol

Volume  = 2500mL  = 2.5L or 2.5dm³

Concentration  = 0.025M

Unknown:

Mass of compound  = ?

Solution:

To solve this problem, we need to find the number of moles from the given concentration and volume values.

     Number of moles  = concentration x volume

So;

      Number of moles  = 0.025 x 2.5  = 0.0625mol

Therefore, mass of compound;

    Mass = number of moles  x molar mass

  Mass  = 0.0625 x 74  = 4.6g

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

the temperature of the gas, in k, not celsius.