How many moles of Fe(OH)2 can be made from the 281 grams of Fe?

You first should calculate the total number of moles of LiOH available.  The LiOH solution is 0.058 molar which means that one liter of solution contains 0.058 moles.  As one liter is 1000 mL, the number of moles per mL is 0.058/1000.  So, the number of moles in 150 mL is 0.058 moles x 150 mL\1000 mL.  The mL units cancel out, so the result is 0.0087 moles of LiOH.  Knowing the number of moles of LiOH allows the calculation for the number of moles of FE(OH)2 by setting up the following proportion:

 0.0087\2 = M/1  where the 2 and 1 are the coefficients for LiOH and Fe(OH)2  in the balanced reaction respectively.  I get a result of 0.0044 moles Fe(OH)2.

Explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

the maximum mass of nh3 is nh3 in grams