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2KCIO3 → 2KCI + 302
How many grams of potassium chloride are produced if 52 g of potassium chlorate decompose?

A )32 g KCI
B )19 g KCI
C)44 g KCI
D)1.5 g KCI

Mass of KCl : 32 g

Given

Reaction

2KCIO₃ → 2KCI + 30₂

52 g Potassium chlorate

Required

Mass of KCl

Solution

mol of KCIO₃ :

= mass : MW

= 52 g : 122.55 g/mol

= 0.424

From equation, mol KCl :

= 2/2 x mol KCIO₃

= 2/2 x 0.424

= 0.424

Mass KCl :

= mol x MW

= 0.424 x 74.5513 g/mol

= 31.6≈32 g

the ratio of the conjugate base to the acid required to attain the desired ph.