A 25.0 g piece of aluminum is heated from 18 oC to 175 oC using 3,533 Joules of heat energy. What is the specific heat of the aluminum? show work pleaseee

The specific heat of the aluminum : c = 0.9 J/g  °C

Given

25 g Aluminum

Temperature from 18°C to 175 °C

Heat = 3.533 J

Required

The specific heat of the aluminum

Solution

Heat can be formulated :

Q = m . c . Δt

Input the value :

c = Q / m . Δt

c = 3,533 / 25 x (175 - 18)

c = 3533/3925

c = 0.9 J/g  °C

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.