C4H10+ 02 → _CO2 + __ H20 a) Balance the equation for the reaction and state what type of reaction it is.
b) How many moles of carbon dioxide are produced in the reaction?

a) 2C4H10 + 13O2 —> 8CO2 + 10H2O. Oxidation reaction

b) 8 (4 moles CO2 per mole butane)

Explanation:

could be written C4H10 + 6 1/2 O2 —> 4CO2 + 5H2O

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.