At least with the first part

The correct answer -

a. Cd and Pb(NO3)2

b. Redox reactions

c. Pb and Cd(NO3)2

Explanation:

This is the reaction known as the redox or reduction-oxidation reaction of metals. In this particular reaction, there are two reactants Cadmium (III) in solid-state and lead (II) nitrate in the aqueous state. At the end of this reaction, the products that we get are lead (II) in solid-state and Cadmium (III) nitrate in the aqueous state.

cadmium (s)+ lead nitrate (aq) = lead (s) + cadmium nitrate (aq)

Cd (s) + Pb2+(aq) → Pb(s) + Cd2+(aq)

Here, Oxidizing agent is Pb2+ and the reducing agent is Cd.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: