An anion reaction with a metal and forms a -3 charge. How many atoms of the metal would be required if the element is in group 1 on the periodic table?

3 atoms

Explanation:

The number of atoms of the metal that would be required as it forms an anionic charge of -3 is 3 atoms.

Elements in group 1 generally have a charge of +1. They have a valency of 1

By the virtue of this;

 It will take 3 atoms of a group one element to combine with an anion with a -3 charge on it.

This way, the ionic bond forms and the compound becomes neutral.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.