If 1.2 g of ammonium bicarbonate is treated with .75 grams of sodium chloride, 63.0075 grams sodium bicarbonate will be produced. In yhis reaction NacI is limiting reagent true or false

NaCl as a limiting reactant ⇒ true

Given

1.2 g NH₄HCO₃

0.75 g NaCl

63.0075 g NaHCO₃

Required

The limiting reactant

Solution

Reaction

NH₄HCO₃ + NaCl ⇒NH₄Cl + NaHCO₃

mol NH₄HCO₃ :

= 1.2 g : 79,056 g/mol

= 0.015

mol NaCl :

= 0.75 : 58.5

= 0.013

NaCl as a limiting reactant(smaller mol)

the answer is d. 74.02