Pedro created the following table for his observations on balanced and unbalanced forces. He forgot to record some of the information. Which two measurements correctly complete the table? A. 50 N in row one and 100 N in row two

B. 100 N in row one and 30 N in row two

C. 100 N in row one and 60 N in row two

D. 90 N in row one and 50 N in row two

Option B. 100 N in row one and 30 N in row two

Explanation:

To know the the correct answer to the question, do the following:

For Row 1:

Force to the right (Fᵣ) = 100 N

Net force (Fₙ) = 0 (since it is balanced)

Force to the left (Fₗ) =?

Fₙ = Fᵣ – Fₗ

0 = 100 – Fₗ

Collect like terms

0 – 100 = – Fₗ

– 100 = – Fₗ

Multiply through by –1

Fₗ = 100 N

For Row 2:

For the net force to be unbalanced, it means that one of the force is greater or lesser than the other.

In the question given above, the force to the left is given as 50 N and it show it is greater than the force to be right. The other force must be lesser than 50 N to result in unbalanced force according to the illustration from the question.

From the options given above, option B has a lesser force (i.e 30 N) for row 2 compared to option C which has a greater force (60 N) for row 2.

Therefore, option B gives the correct answer to the question.

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation: