N2 + 3H2 → 2NH3 How many moles of NH3 could you make with 4.2021 g of N2?

I need this like rn pls .

Moles of NH3 = 0.3 moles

N2 + 3H2 → 2NH3

4.2021 g of N2

Required

moles of NH3

Solution

mol N2 :

= 4.2021 g : 28 g/mol

= 0.15

From the equation, mol NH3 :

= 2/1 x mol N2

= 2/1 x 0.15

= 0.3 moles

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

it is a solid

explanation: