Calculate the solubility at of in pure water and in a solution. You'll find data in the ALEKS Data tab lead chromate.

1.34 * 10^-7 M

Explanation:

The Ksp of lead II chromate is 1.8 x 10^-14

So, we have that;

PbCrO4(s) > Pb^2+(aq) + CrO4^2-(aq)

                             s                  s

Where s = molar concentration of Pb^2+(aq) and  CrO4^2-(aq)

and;

[Pb^2+] = [CrO4^2-]

This implies that Ksp = s^2

s = √Ksp

s = √1.8 x 10^-14

s = 1.34 * 10^-7 M

catya your not at all which answer i've seen you do this on another question!