The door to the classroom weighs 3 kg. How much work is done when Michael pushes on the door to the classroom with 15 Newtons of force, pushing the door 1.3 meters?

Work done : 19.5 J

Given

F = 15 N

d = 1.3 m

m = 3 kg

Required

Work done

Solution

Work is the product of force with the displacement of objects.  

Can be formulated  

W = F x d  

W = Work, J, Nm  

F = Force, N  

d = distance, m  

Input the value :

W = 15 N x 1.3 m

W = 19.5 J

the mass has no effect on this problem

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates