An arctic weather balloon is filled with 4.96 L of helium gas inside a prep shed. The temperature inside the shed is 6. °C. The balloon is then taken outside, where the temperature is 2. °C. Calculate the new volume of the balloon.

The new volume of the balloon : V₂ = 4.89 L

Given

V₁ = 4.96 L

T₁ = 6 + 273 = 279 K

T₂ = 2 + 273 = 275 K

Required

The new volume

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

Input the value :

V₂=V₁.T₂/T₁

V₂ = 4.96 x 275 / 279

V₂ = 4.89 L

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

the temperature of the gas, in k, not celsius.