There's 4.1*10^25 particles of calcium phosphate, how many grams of calcium phosphate is that

Mass of Calcium phosphate : = 21127.7 g

Given

4.1 x 10²⁵ particles of Calcium phosphate

Required

mass

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

mol Calcium phosphate :

n = N : No

n = 4.1 x 10²⁵ : 6.02 x 10²³

n = 68.11

mass Calcium phosphate Ca3(PO4)2 :

= mol x MW

= 68.11 x 310.2 g/mol

= 21127.7 g

= 21.13 kg

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it