the pressure of 1 mol of gas is decreased to 0.05 atm 273.k. what happens to the molar volume of the gas under these conditions?

The molar volume of the gas : V = 447.993 L

Given

n = 1 mol

P = 0.05 atm

T = 273 K

Required

The molar volume

Solution

Ideal gas law :

PV=nRT

V = nRT/P

Input the value :

V = 1 x 0.08205 x 273 / 0.05

V = 447.993 L

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

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